0:00
lastly we have to find the constant C
0:03
the value of the y intercept of the
0:05
tangent line we already have the
0:07
gradient of the tangent line given by
0:09
the first derivative of the function gx
0:11
hence given as gx = -x cub - 2x^2 + 11 x
0:15
+ 12 so let's find the first derivative
0:18
of gx by using the power rule from step
0:21
one at which we found the gradient to be
0:23
-8 we also have the coordinates of the
0:26
point of tangency on the curve whereby
0:28
we substituted the xcoordinate into the
0:30
original function gx and that will be
0:32
giving us the y-coordinate of the point
0:34
where the tangent touches the curve that
0:36
means we can find the equation of the
