0:00
hello welcome to we learn daily in this
0:03
video I'll show you how to find the area
0:06
of a triangle inside a rectangle given
0:08
that the areas of the other triangles
0:10
are 6 20 and 21 square
0:14
units as always to assess the difficulty
0:18
pause the video and try to solve the
0:20
problem on your own let's start by
0:22
denoting the legs of the right triangles
0:24
on one side of the rectangle As A and B
0:28
this means the entire side of the
0:30
rectangle will be equal to a + b now
0:34
let's denote the legs on the other side
0:36
of the rectangle as C and D therefore
0:41
the entire side of the rectangle will be
0:44
C + D next we'll express everything
0:47
given using a b c and d we'll start by
0:51
recording the area of each right
0:53
triangle as half the product of its legs
0:56
so we get that the area of the first
0:57
triangle is equal to a * C + D / 2 and
1:04
21 for the second triangle we get D * A
1:08
+ B / 2 and this equals
1:12
20 and for the third triangle we get B *
1:15
C / 2 and this equals 6 we multiply both
1:20
sides of each equation by two and for
1:23
the first two equations we can expand
1:25
the brackets to find the area of the
1:27
triangle inside the rectangle we can
1:29
calculate the area area of the entire
1:30
rectangle and then subtract the known
1:34
triangles the area of the rectangle is
1:36
equal to the product of its two sides
1:39
after expanding the brackets we have a *
1:41
C + a * D + B * D + B * C now we can
1:45
observe that a * C + a * D according to
1:50
the conditions equals 42 we also know
1:53
that a * D + B * D according to the
1:56
conditions equals 40 and B * C = 12 to
2:01
find the right side we are missing one a
2:03
* D if something is missing we need to
2:06
add it so let's add a * D to each part
2:10
of the last equation in the left part we
2:13
get the area of the rectangle plus a * D
2:16
on the right side we get 42 + 40 + 12
2:20
which equal 94 now we need to express
2:24
the area of the rectangle using a * D
2:27
let's multiply both sides of the
2:29
previous equation by a * D then the area
2:32
of the rectangle multipli a * D will
2:35
equal a * D * a + b and a c plus D since
2:41
we already know the products we
2:43
substitute the known values into the
2:45
equation as a result we obtain 40 * 42
2:51
for Simplicity let's denote the area of
2:53
the rectangle as X and express a * D
2:57
from the first equation and substitute
3:01
equation expanding the brackets and
3:03
transferring everything to the right
3:05
side we obtain a quadratic equation
3:08
since the sum of these roots equals 94
3:10
according to vieta's theorem X can be
3:13
equal to 70 or X can be equal to the
3:16
other possible root however X represents
3:20
the area of the entire rectangle which
3:22
already includes the three right
3:24
triangles with a total area greater than
3:27
24 thus there is only one possible value
3:32
rectangle the area of the rectangle is
3:34
70 square units so the area of the
3:38
triangle we need to find will be the
3:39
difference between 70 and the sum of the
3:41
areas of the three other triangles let's
3:44
write down the answer the area of the
3:47
triangle is equal to 23 square
3:52
solved if you understood the solution
3:55
give it a like leave a comment and don't
3:57
forget to subscribe to the channel
4:00
thank you for watching I hope to see you