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Hello everyone, welcome to automation
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community. Today in this video we are
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going to discuss an example in which we
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will be drawing ladder diagram for
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boolean expressions. So let's look at
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Example 38 y1 is equal to a1
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dot b1. And the second one is y2 is
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equal to a2 dob b2 plus c2 dot d2.
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So for the b first boolean expression
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we have two inputs to turn on output y1.
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So for a1 there is a not there. So we
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will use a normally closed contact for
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a1 and a normally open contact for b1.
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And we will connect these two contacts
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in series. So there is and logic gain
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between A1 and B1. And for the second
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boolean expression we have four inputs
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A2 B2 C2 and D2. So A2 and B2 will be
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connected in series and C2 and D2 will
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be connected in series but in parall to
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A2 dot B2. So let's move to codicuses
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where we will draw the ladder diagram
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for these boolean expressions one by
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So I will open cortices.
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Let's create a new project. First we can
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write the name of the project here.
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13. We can also select the location
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where this file will be saved. We can
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also use a template. We can select it as
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standard project and click on open.
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We can select this device from this
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drop-own list and select PLC programming
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as ladder logic diagram and then click
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So click on double click on PLC
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programming. So here we will draw the
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ladder diagram. So we have two inputs A1
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and B1. There is A1 do A1 not dot B1. So
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for A1 we will use a normally closed
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contact. So I will insert a normally
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closed contact for A1 and I will insert
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a normally open contact for B2. And I
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will insert a coil for Y1.
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and then this will be y1.
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So the coil will be used for y1 output
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And then we have another boolean
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expression that is a2 d2 + c2 d2. So uh
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a2 and d2 will be connected in series.
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Okay. So I will insert one more network
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below. So here we will insert two
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normally open contacts. So this will be
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a2. Okay. And this normally open contact
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will be b2. So it was A2 dot V2
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and then we have plus sign that means
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there will be or logic 8. So uh we have
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C2 and D2 that will be connected in
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parallel with this A2B2.
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So here we need to select both these. I
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Press shift. Keep pressing the shift
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button. Then click on B2 and then insert
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contact parallel to this and then delete
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So this normally open contact will be
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C2. Okay. And we need to add one more
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normally open contact. This will be D2.
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Okay. So this is A2 dot B2 plus C2. D2.
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And then we will insert a coil and this
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So this output Y will be on.
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Okay. So, Y1 will be on when A1 is off
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and B1 is on. Okay. So, for output Y1 to
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be on, A should be off and B should be
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on. And then for output Y to be on,
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either A2 and B2 both should be on or C2
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and D2 both should be on. If A2 and D2
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are on, then output Y2 will not be on
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either. If A1 A2 is on then with that B2
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should be on then only output Y2 will be
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on and then if C2 is on then with that
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D2 should be on then Y2 will be on.
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Okay. So let's generate code.
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Go to online start simulation
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and then start. Okay. So for now A1 is
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off and we need to turn on B1 to turn on
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Y1. So I will make it true. I will make
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B1 true and then go to debug and write
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values. And you can see Y1 is on. If I
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turn on A1 as well. I will make it true.
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Go to debug and write values. Then you
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can see the signal will not pass through
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this because this is a normally closed
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contact. In true state the signal will
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not pass through this. As a result, this
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Y1 will not turn on. It will turn off.
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And then for output Y2 to be on, we need
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and B2. Let's debug it. Write values.
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You can see here Y2 turned on when I
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turned on A2 and B2. If I turn off B2,
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you can see here the debug and write
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value. You can see Y2 is off when I turn
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off B2. And then I will turn off A2
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and turn on C2 and D2. And you can see
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when I turn on C2 and D2, Y2 turn on. If
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I turn off D2 or C2, when I turn off D2,
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the output Y2 will turn off. So output
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for output Y2 be Y2 to be on A2 and B2
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both should be on or C2 and D2 both
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should be on. It was all about this
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example. Thank you for watching.
