0:00
solve the equation x ra 9th power - x
0:04
Cub = 6 as usual pause the video before
0:08
watching further and try to solve it on
0:10
your own if there's an opportunity to
0:12
simplify the process we should take
0:15
advantage of it therefore in this case
0:18
let's try to make it easier by
0:19
substitution for example let's denote X
0:22
cubed as T then x raed to the 9th power
0:25
can be written as X cubed all Rays to
0:28
the thir power - x Cub let's write it
0:32
this way and move the number six
0:33
immediately to the left side with a
0:35
negative sign now we can substitute the
0:38
new variable T in place of X cubed as a
0:41
result we get T Cub - t - 6 = 0 this
0:45
equation can be solved in various ways
0:49
for example we could try to find one of
0:51
the roots among the divisors of the
0:53
constant term however we'll take a
0:56
different approach we'll try to factor
1:01
grouping to do this we'll add and
1:04
subtract T cubed using the difference or
1:08
sum of cubes for example from the number
1:11
-6 on the left side of the equation
1:13
we'll subtract two but to ensure nothing
1:16
changes we'll also add two then we'll
1:21
group8 with t cubed and leave 2 with - t
1:25
so on the left side of the equation
1:27
we'll have t Cub - 8 - t + 2 all
1:31
equaling 0 8 is 2 cubed so we've now
1:35
obtained the necessary difference of
1:37
Cubes T Cub - 2 Cub we still have - t
1:41
and -2 and all of this equals z let's
1:46
expand the difference of Cubes using the
1:47
standard formula we'll get the
1:49
difference of these numbers T minus 2
1:52
multiplied by the incomplete square of
1:53
their sum that is ultied T ^2 + 2 t + 4
1:58
we still have t and 2 and all of this
2:01
must equal 0 tus 2 can be factored out
2:04
inside the parentheses we are left with
2:06
t ^2 + 2 t + 4 - 1 and all of this must
2:11
equal zero so we finally have t - 2 *
2:15
t^2 + 2 t + 3 equaling 0 the product of
2:20
two polinomial equals 0 when at least
2:23
one of them equals z however since the
2:25
discriminant of the quadratic trinomial
2:27
is less than zero the second polinomial
2:29
has no real Roots therefore the left
2:32
side of our equation equals 0 only when
2:34
the first Factor T minus 2 equal 0 from
2:37
this T must equal 2 returning to the
2:41
original variable we find that X cubed
2:44
must equal 2 from which x equal the cube
2:48
root of 2 write the answer the equation
2:51
has a unique solution X must equal the
2:54
cube root of two the problem is solved
2:57
if you understood the solution give give
2:59
a thumbs up leave a comment and don't
3:02
forget to subscribe to the channel