How To Find The LCD & Simplify More Complex Rational Expressions
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Feb 20, 2025
Today we worked on using the lowest common denominator of a rational expression to simplify it. During our lessons , we also learned how to solve equations involving fractions. For more lecture visit http://tayibs.com/get-math-help/
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so a couple of weeks ago we worked on
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like simplifying fractions and rational
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expressions and now it's getting a
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little bit more complicated and today
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what we have is this expression here as
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a fraction and on top of another
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fraction and we have to learn to
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simplify them now the first thing we
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want to do is find the lowest common
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denominator and then when we find the
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lowest common denominator we can use the
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quotient rule and just flip the bottom
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one and factor it right so let's let's
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write down the equation so is 1 over X
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plus 2 minus 2 okay
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the whole thing over 4 over X plus 2
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plus 2 I'm going to split this into two
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I'm gonna take the numerator and I'm
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gonna take the denominator apart and I'm
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gonna work on this together right so the
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first thing we have is 1 over X plus 2
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minus 2 and I want to find the lowest
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common denominator all right
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so this fraction is like over 1 right
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yeah so the thing is this what is very
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simple this fraction the X plus 2 I want
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to make this college this denominator is
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the same right so it's gonna be since
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they don't have anything in common so
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the lowest common denominator LCD
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something why is with 1 times X plus 2
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right I'm gonna put in parentheses
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because you wanna you want to make sure
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these two fractions have the same
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denominator you cannot add any fractions
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or subtract any fraction if they don't
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have the same denominator okay so now
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here's what I'm gonna do here I'm gonna
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transform this one into X plus 2 and I'm
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gonna multiply this one by one
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right which is doesn't do much to it
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they stay the same and I'm gonna
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multiply this one by X plus 2 I'm gonna
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put a parenthesis to make it easier but
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here's the thing when I do something to
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the denominator I have to do the same
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thing on the numerator - the numerator
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right so there's gonna be X plus 2 so we
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end up having 1 over X plus 2 minus 2 X
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plus 2
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over X plus 2 and then we can put these
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two fractions together since they are
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the same denominator we can just put
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them into one single denominator which
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is X plus 2 or once you get them all
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like all the same yes put him on you
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don't have to if it's both the same
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thing you just pull on one first that's
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the whole point is to put him together
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right over 2 X plus 2 right and then
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we're gonna do this with an X 1 with
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this expression here alright same thing
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so we're just gonna jump to the you know
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burn all those steps and we're not gonna
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wish our time because we already know
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what to do there so the denominator is
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gonna be Express to steal right and I'm
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gonna multiply the 2 times X plus 2
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right because we did the same step here
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it's the same denominator and he's like
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a similar fraction so we're not gonna
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waste time trying to elaborate on every
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single piece all right now we can put
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them back together so now we have the
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first fraction which is 1 minus 2x plus
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2 over X plus 2 right over 4 plus 2x
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plus 2 over X plus 2x plus 2 correct it
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looks but it's not complicated so I'm
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gonna take this expression and this is
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the thing I'm going to keep this the
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same and I'm gonna flip this one right
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because that's how your quotient rule
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I'm gonna recall the question will a
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over B divided by C over D is equal to a
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times D right over a times e over BC
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okay so this is the same process here
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I'm gonna be times B times C is being
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the same alright so we're gonna do the
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same thing here so we're gonna take 1
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minus 2 X plus 2 right and I know it
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looks really complicated but it's not
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okay you're gonna see how I wanted to
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explain something to you first and then
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we're gonna multiply it by the
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reciprocal right which is X plus 2
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over 4 right + 2 X plus 2 all right and
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then look what can I do with these two
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here
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cross and cross them up right so I'm
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left with 1 minus 2x plus 2 over 4 plus
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2x plus 2 now the last step would be
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sorry
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look at Ben so I was fresh nothing too
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much the last thing would just be to
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split this to work on it at the top one
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right we're gonna multiply the h1 101
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minus 2 X minus 2 right / 4 + 2 X + 4
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okay this is crazy to read this over 1
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minus 2 X but my - follow me I can't
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multiply guys forgive me for that now
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it's gonna be negative 3 minus 2x over 8
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plus 2 X we combining like terms
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okay and that should be the final result
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only here goes you just you just can the
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second problem in this case we have a
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second-degree expression and we have to
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turn around simplify this so I actually
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wrote out the steps and I'm gonna just
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go through them one at a time so the
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first thing we want to do is just single
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out on the numerator and that's what we
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need over here and then we want to find
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the lowest common denominator now to
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find the lowest common denominator we
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have to factor on this expression
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alright expression and I want two
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numbers whose product is negative 6 and
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Psalms 5 so we have 6 and 1 and since
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this is negative and this is positive so
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it's gonna be 6 and then X plus 6 and X
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minus 1
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so we split that and then we do the same
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thing over here now we want to find the
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LCD because this is X minus 1 they
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already have X minus 1 in common so all
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I need to add is X plus 6 which I did on
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both sides like because if you do
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something in the denominator you have to
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do the same thing on the numerator and
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then now we have the same expression
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here now we put them into one single
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fraction denominator okay and then the
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next thing is we
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do the same thing with our within
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denominator which is right here since
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they have the same exact denominators I
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just went ahead and just put this on top
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of that okay so I hope you understand
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what I'm doing here and then the next
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thing is just to flip this fraction
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because we're using the quotient rule
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and our division rule or whatever and
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we're gonna just simplify the like terms
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which are cut out and then we're gonna
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do it use the distribution rule here and
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we end up with this which is simplifying
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combining like terms so you get up to
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negative 5 minus 6 over 10 plus X 9 DX
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hopefully you get what I'm saying
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because I had to just write out except I
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didn't wanna do them you know I was I
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was working so this is clear enough all
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right if you have any questions be sure
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to just send me a email all right we
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went from basically simplifying
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fractions to not solving equations are
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you sleepy so we're gonna be doing the
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same thing here now before we solve it
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we have to find a common denominator for
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these two fractions okay now one is
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people say that some fraction one is one
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over one basically right so again one
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over one I keep on breaking order spread
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because you sharpen them too much 1 over
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1 right 1 over 1 and the common
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denominator will be n right now here's
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the key a lot of people like to like
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complicate things but what I do is this
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I know that if I multiply every single
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entry by n I'm gonna simplify this and
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make the problem a lot easier so I'm
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going to put a renters here I multiply
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this by n and n because every single
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entry here has can be if I if I was
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trying to find a common denominator
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right for each of this fraction ub n for
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this one and for this one and i have to
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turn this into 1 times n right so if I
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do that I'll make my problem 7 because I
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multiply everything by n guess what's
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gonna happen this squad cancel this one
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right it's gonna cancel this one and I'm
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gonna be left with 3 and square
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Plus 10 and - train right - N equals to
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2 because if you multiply n times these
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it gives you n right and then now you
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can solve this problem cause it's a lot
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easier to work with now you see what I'm
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saying yeah so now what we have is we
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can put all on one side so we're gonna
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do 3n squared plus 10 and minus 10 minus
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n minus 2 equals to 0 okay and that
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gives you 3 n squared plus 10 N and then
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negative 10 minus 2 is negative 12 but
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we're gonna put it in order 10 n minus n
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is 9 in so I should make it easier I
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don't want me I'll see y'all come behind
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ya combine like terms right minus 12 is
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equal to 0 now look it's a lot easier
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now they all have white in common and
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and but at the same time is the second
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degree right in black and Pilate 3
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correct travellightly 300-watt n square
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plus 3 n minus 4 equals to zero and I
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can solve this because now I want two
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numbers whose product is 4 negative 4
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and some Street right 4 & 1 oh you just
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turn it into a second factor Buffon
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right so I've got my 3 here so then we
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end and and she's a negative so it's
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gonna be plus 4 minus 1 and all I have
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to do is set each one of these equal to
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0 solve for n I can let you do that
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alright so hopefully it makes sense okay